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What will be the Output of the following pseudocode?
a=0
b=7
def fun(a,b):
if ((b<7 or 3>a) and 3<b):
a=2+a+a
a=b+2
a=3+1+a
return fun(a,b)
return b
print(fun(a,b))
Ans : 7
What will be the Output of the following pseudocode?
def fun(a, b):
if ((b^a)<(a+b) and (a&b)<(b-a)):
b=a+1+a
a=3+a+b
a=1+b+b
return 1+fun(a+1,b+2)+2
return a-1
print(fun(3,7))Ans : 18
What will be the Output of the following pseudocode?
p=9
q=4
r=6
r=(r^p)^q
q=(p+q)&p
print(p+q+r)Ans : 29
What will be the Output of the following pseudocode?
pp=2
qq=7
rr=7
for rr in range(4,6):
if(3<qq):
qq=qq+pp
qq=7+rr
qq=(rr+3)^qq
print(pp+qq)Ans :6
Accenture Pseudo Code
What will be the Output of the following pseudocode?
a=4
b=6
c=4
for c in range(3,7):
b=(c&9)&b
b=(2^10)^a
c=(c+c)+b
print(a+b)
Ans: 16
What will be the Output of the following pseudocode?
a=4
b=6
c=4
for c in range(3,7):
b=c&c
b=(a^a)&b
print(a+b)
Ans : 4
What will be the Output of the following pseudocode?
def fun(a, b):
if ((4-a)>(a-b) and a<4):
a=3+2+a
a=3+1+a
a=1+3+b
return a+fun(a,b)+fun(a,a)
return a+b
print(fun(0,0))Ans : 16
What will be the Output of the following pseudocode?
def fun(a, b, c):
if((c+a)<(b-c)):
c=(c+8)+b
if(4>b and (c&b)<b):
c=(a+7)+b
else:
c=a&c
return a+b+c
print(fun(3,5,10))
Ans : 10
Accenture Pseudo Code
What will be the Output of the following pseudocode?
def fun(p,q,r):
for r in range(3,7):
q=r&r
q=(p^p)&q
return p+q
print(fun(9,5,8))
Ans : 9
What will be the Output of the following pseudocode?
def fun(p,q,r):
if((1+p)<q or (r+3)<3):
q=9+q
if((q+p+r)<(r+6)):
p=(p+p)+q
r=q+p
return p+q+r
print(fun(1,2,10))
Ans: 13
Accenture Pseudo Code
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