Numerical Ability
Question 1
Answer
Explanation
Question 1
When the List Price (LP) of an article is fixed at 30% above the Cost Price (CP), and while selling the same, it is subject to a discount of x%, the profit percentage is 80% of that when the LP is fixed at 25% above the CP and the discount is 16%. What is the value of x?
A. 3.6
B. 3.25
C. 3
D. 3.84
Answer
All the answer options are wrong.
Correct Answer: 20
Explanation
Let, cost price of the article is = Rs. 100
In the first case, List price will be = Rs. 130
Selling Price = 130*(100-x)/100 = (1300-13x)/10
In the second case, List price = Rs. 125
Selling price = 125*84/100 = Rs. 105
ATQ, (105-100)*80/100 = (1300-13x)/10 – 100
=> 4 = 30 – 1.3x
=> x = 20
Question 2
Answer
Explanation
Question 2
A sum invested in compound interest (CI) at a certain rate for three years earns the same interest as it would earn by way of an investment in simple interest (SI) at the rate of 18.2% for four years. How much more or less is the percentage rate in case of the CI than that in the case of the SI?
A. 21.25
B. 18.43
C. 16.52
D. 20.63
Answer
All the answer options are wrong.
Correct answer: +1.8%
Explanation
Let the sum is P , and CI rate is R% per annum.
Putting all values we get,
P[{1 + (R/100)}³ – 1] = (P * 18.2 * 4)/100
=> {1 + (R/100)}³ – 1 = (728/1000)
=> {1 + (R/100)}³ = (1728/1000)
=> {1 + (R/100)}³ = (12/10)³
=> {1 + (R/100)}³ = {1 + (2/10)}³
=> {1 + (R/100)}³ = {1 + (20/100)}³
=> R = 20% per annum .
Difference between rate = 20 – 18.2 = 1.8%
Question 3
Answer
Explanation
Question 3
What is the fourth proportional of the mean proportionals between (4, 6.25); (0.0027, 300)::
(1.2 X 10^-3, 3)?
A. 4.8
B. 48
C. 36
D. 3.6
Answer
All the answer options are wrong.
Correct answer: 0.0108
Explanation
(4, 6.25) = a
(0.0027, 300) = b
(1.2*10^-3, 3) = c
? = d
a:b::c:d
Mean Proportional of a = 5
Mean Proportional of b = 0.9
Mean Proportional of c = 0.06
a/b = c/d
d = 0.0108
Question 4
Answer
Explanation
Question 4
In a competitive exam, 5 marks are awarded for every correct answer and for every wrong answer, 2 marks are deducted. Sathwik and 32 marks in this examination. If 4 marks has been awarded for each correct answer and 1 mark had been deducted for each incorrect answer, Sathwik would have scored 34 marks. If Sathwik attempted all the questions, how many questions were there in the test?
A. 20
B. 14
C. 12
D. 26
Answer
D. 26
Explanation
Let Sathwik answered x right questions and y wrong questions.
Then total number of questions = x+y
The marks Sathwik scores in the examination = 5x-2y
5x-2y = 32 …i
Now if 4 marks are awarded for every correct answer and for every wrong answer, 1 marks are deducted.
The marks Sathwik scores in the examination = 4x-y
4x-y = 34 …ii
Now Solving Equation (i) & Equation (ii) ->
x=12, y=14
Total questions = (12+14) = 26
Question 5
Answer
Explanation
Question 5
What is the difference between the Range and the Standard Deviation of all the natural numbers between 81 and 90, both inclusive?
A. 7
B. 11
C. 9
D. 8
Answer
All the answer options are wrong.
Correct answer: 7.13
Explanation
range of numbers 81,82,83,84,85,86,87,88,89,90.
maximum – minimum = 90-81+1 = 10
and the standard deviation is 2.87
Difference = 10-2.87 = 7.13
Also Checkout: TCS NQT Sample Question Paper
Question 6
Answer
Explanation
Question 6
The area of a sector, with central angle 15 deg, of a circle is 231 sq cm. If 𝚷 = 22/7, what is the circumference (in cm) of the circle?
A. 2.8
B. 1.45
C. 2.1
D. 2.45
Answer
All the answer options are wrong.
Correct answer: 264
Explanation
(22/7) * r * r * 15/360 = 231
=> r = 42
Circumference = 2*(22/7)*42 = 264
Question 7
Answer
Explanation
Question 7
A takes 10 days less than B to complete a work, and together they do it in 12 days. In how many days can B alone do the work?
A. 9
B. 12
C. 10
D. 6
Answer
All the answer options are wrong.
Correct Answer: 30 days
Explanation
Let’s B alone take x days to finish the work.
B’s 1 days work = 1/x
A alone can finish the work in = x – 10
A’s 1 days work= 1/(x-10)
ATQ, 1/x + 1/(x-10) = 1/12
(2x -10) / (x² -10x) = 1/12
x² -34x +120 = 0
(x-30)(x-4)= 0
x = 30 or x= 4
The value of x cannot be less than 10, so x=30
Question 8
Answer
Explanation
Question 8
The sum of ages of two friends is 74. After one year the ratio of their ages will be 9:10. What was the ratio of their ages nine years ago?
A. 4:3
B. 3:2
C. 13:12
D. 7:6
Answer
All the answer options are wrong.
Correct Answer: 13:15
Explanation
Let, Individual ages are x yrs and y yrs.
x+y = 74
(x+1)/(y+1) = 9/10
=> (75-y)/(y+1) = 9/10
=> 750-10y = 9y+9
=> y = 39
=> x = 35
Ratio 9 years ago = 26:30 = 13:15
Question 9
Answer
Explanation
Question 9
In case of frequency distribution for ten continuous classes, the class width is 4 and the lower class limit of the lowest class is 8. What is the upper class limit for the highest class?
A. Both R&S
B. R Only
C. Neither R nor S
D. S only
Answer
All the answer options are wrong.
Correct Answer: 48
Explanation
If x and y are upper and lower class limits
then x-y = 4 ; y = 8
x=12 means upper limit of lower class
now for upper limit for the highest class = no.of continuous class * class width + lower class limit
= 10*4 + 8 = 48
Question 10
Answer
Explanation
Question 10
10 men can complete a work in 8 days and 10 women take 12 days to complete the same work. How many days will 3 men and 6 women take to complete the same work?
A. 11(3/7)
B. 9(3/7)
C. 10(3/7)
D. 12(3/7)
Answer
A. 11(3/7)
Explanation
10 men can complete a work in = 8 days
3 men can complete a work in = 8*10/3 = 80/3 days
10 women can complete a work in = 12 days
6 women can complete a work in = 12*10/6 = 20 days
3 men and 6 women will take = (1/(3/80+1/20))=80/7 = 11(3/7) days
Question 11
Answer
Explanation
Question 11
The percentage marks scored by two students A and B at four consecutive monthly tests are depicted in the Bar Graph given below. In which month is the percentage marks scored by B 40% more than that by A?
A. 2014
B. 2013
C. 2012
D. 2015
Answer
All the options are wrong
Correct Answer: August
Explanation
In August, (70-50)*100/50 = 40%
Also Checkout: TCS NQT Sample Question Paper
Question 12
Answer
Explanation
Question 12
A sales representative’s commission is 6% on all sales up to Rs.15000 and 5% on all sales exceeding this. He remits Rs.47350 to his company after deducting his commission. What were the total sales?
A. Rs.50000
B. Rs.49000
C. Rs.47500
D. Rs.50500
Answer
A. Rs.50000
Explanation
Let, Total Sales = x
Total Commission = y
Then according to the given conditions,
0.06*15000 + 0.05 (x – 15000) = y …1
47350 + y = x …2
On simplifying 1, we have
900 + 0.05x – 750 = y
Therefore, y – 0.05x = 150 ………E3
On simplifying E2, we have
x – y = 47350 ………E4
To solve this, adding E3 & E4, we get
0.95x = 47500
Therefore, x = 50000
Hence, the total sales is Rs. 50000
Question 13
Answer
Question 13
What is the simplified value of:
A. 4
B. 5
C. 6
D. 2
Answer
B. 5
Question 14
Answer
Explanation
Question 14
With symbols having their usual meanings the mean of the data given below is 39.2.
x 36 40 35 44
f 10 13 12
What is the missing frequency?
A. 125.2
B. 124.6
C. 124.2
D. 123.8
Answer
All the answer options are wrong.
Correct answer: 15
Explanation
Let, x is the missing frequency.
(36*10 + 40*13 + 35*12 + 44*x)/(10+13+12+x) = 39.2
=> x = 15
Question 15
Answer
Explanation
Question 15
What is the mean Deviation from the median for the data given below?
Data: 34, 46, 28, 48
A. 64
B. 53
C. 66
D. 51
Answer
All the answer options are wrong.
Correct answer: 8
Explanation
Sort the data: 28, 34, 46, 48
median = (34+46)/2 = 40
number of data = 4
sum of (d-x) = 32
Mean Deviation = 32/4 = 8
Question 16
Answer
Question 16
The table below presents the data of atmospheric pressure (in area of mercury) at a place at four different times of the day during four days P, Q, R, S. A steady rise in atmospheric pressure indicates a fair weather. On which of the given days was the weather fair?
A. 324:283
B. 81:73
C. 326:293
D. 28:25
Answer
All the answer options are wrong.
Correct answer: C
(Also please note that Days are marked as P, Q, R, S in the question but in the options it is given
as A, B, C, D)
Question 17
Answer
Question 17
A shopkeeper calculated his profit as 12% with the selling price of an article as the base.What would have been his actual profit percentage if the selling price was 20% more?
A. 20
B. 24
C. 23
D. 21
Answer
All the answer options are wrong.
Correct Answer: 36.66%
Question 18
Answer
Explanation
Question 18
Q13. The total surface area of a solid hemisphere is 75 times the area of a circle whose
diameter is 6 cm. What is the radius (in cm) of the hemisphere?
A. 80π
B. 120π
C. 100π
D. 50π
Answer
All the answer options are wrong.
Correct Answer: 15
Explanation
Let the radius of the hemisphere = r
Total surface area of solid hemisphere = 75 * pi * (3)^2
3*pi*r*r = 75*pi*3*3
=> r = 15
Question 19
Answer
Explanation
Question 19
A shopkeeper calculated his profit as 12% with the selling price of an article as the
base.What would have been his actual profit percentage if the selling price was 20% more?
A. 20
B. 24
C. 23
D. 21
Answer
All the answer options are wrong.
Correct Answer: 36.36%
Explanation
let cost price = 100
12% with the selling price, then CP will be = 100-12% = 88
Profit is calculated by taking selling price was 20% more = 120
Therefore profit over cost price = (120-88)*100/88 = 36.36
Also Checkout: TCS NQT Sample Question Paper
Question 20
Answer
Explanation
Question 20
A sum invested on simple interest grows to Rs 22500 and Rs 25500 in seven and nine years respectively. What is the rate percentage of the interest?
A) 7.5
B) 9.6
C) 13.5
D) 12.5
Answer
D) 12.5
Explanation
Total interest in two years = 25500-22500 = 3000
Total Interest in 9 years = 9*3000/2 = 13500
Principal, P = 22500 – 13500 = 12000
By, formula of Simple interest ->
SI = P*R*T/100
=> 13500 = 12000*R*9/100
=> R = 12.5
Question 21
Answer
Explanation
Question 21
If 5^X3^Y = 225 x 405, find the value of X^2Y-3X
A) 81
B) 27
C) 125
D) 25
Answer
B) 27
Explanation
225 = 5^2 * 3^2
405 = 5^1 * 3^4
Their product = 5^3 x 3^6
So, X=3 and Y=6
3^(12-9) = 3^3 = 27
Question 22
Answer
Explanation
Question 22
The mean of set data is 5. What will be the mean if 10 is subtracted from each data.
A) 5
B) 10
C) -5
D) -15
Answer
C) -5
Explanation
Let, Total data points = n
Mean of Data set = 5
Total of Data set = 5n
If 10 is subtracted from each data point, 10n will be subtracted as a whole.
New Total = 5n-10n = -5n
New Mean = -5n/n = -5
Question 24
Answer
Explanation
Question 24
After purchasing two copies of the same book, X sold them respectively at 0.8 and 1.4 times their cost prices. What was the percentage gain earned or loss incurred by X?
A) 5% gain
B) 10% gain
C) 5% loss
D) 10% loss
Answer
B) 10% gain
Explanation
Let the CP of each copy = 100
ATQ, One copy is sold at = 0.8 x 100 = 80
Other copy is sold at = 1.4 x 100 = 140
Total money spent = 200
Total money earned = (80+140) = 220
Total gain = 20
Therefore gain% = (20/220) x 100 = 10%
Question 25
Answer
Question 25
The percentage marks scored by two students A and B at four consecutive monthly tests are depicted in the Bar Graph given below. In which month is the percentage marks scored by B 40% more than that by A?
A. 2014
B. 2013
C. 2012
D. 2015
Answer
All the options are wrong
Correct Answer: August
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