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Capgemini Pseudocode Solved | Set 3 – codewindow.in

/ Capgemini Pseudocode / By 
Input array elements 1,2,3,4,5,6,7,8
Initialize n as number of elements
FUNCTION ch(input num){
INITIALIZE r_num=0, r
if(num!=0)
r=num%10
r_num=r_num*10+r
ch(num/10)
ENDIF
return r_num
ENDFUNCTION
FUNCTION main()
int num, r_num;
READ num equals to 142
r_num = ch(num);
if(num==r_num)
WRITE ”YES”;
else
WRITE “NO”;

Initialize sum equals 0

i=n-1
Function
SUM(array,i,sum) If(i<0)
Write sum
if((ar[i]%2==1)
sum+=(ar[i])
SUM(array,i-1,sum)
ENDIF
ENDFUNCTION
32.input a=8,b=16
int fun(int a,int b)
{
int n=0
if(b<1)
return n
else
return fun(a+b+2,b-2)
}

Integer a,b,c,d
Set a=14,b=15,c=16

If(a>6)
    b=c-a
    if(a>c)
        d=b+c
    else
        d=b-c
else
    d=a+b+c-3
print d
Function Sum(int num) (<> not equals to)
If(num<>0)
Return num+num*sum(num-1)
Else
    Return num
END if
END function
Integer n,beg,end

Set beg=5,end=7,sum=0
If(beg>end)
Print sum+1
Else
For(n=end;n>=beg;n=n-1)
Sum=sum+n
N=n-1
End for loop
Print n

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struct{
short s[5]
union{
float y;
long z;
}u;
}t;
bin1=1010 bin2=1000
READ input bin1,input bin2
INITIALIZE i equals 0,rem equals 0
INITIALIZE array ar of size 20

While(bin1!=0 or bin2!=0)
sum[i++]=(bin1%10+bin2%10+rem)%2
rem=(bin1%10+bin2%10+rem)/2
bin1=bin1/10
bin2=bin2/10
EndWhile
If(rem!=0)
sum[i++]=rem
--i
Endif
While(i>=0)
Print sum[i--]
EndWhile

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num=12
FUNCTION factor(input num)int
i,j,primeno; for(i=2;i<=num;i++)
if(num%i==0)
SET primeno as TRUE
Endif
Endfor
for(j=2;j<=i/2;j++)
if(i%j==0)
SET primeno as FALSE

Break
Endif
Endfor
If primeno is TRUE
WRITE i
Read array a[5]={5,1,15,20,25}
Initialize i, j, m
i=++a[1]
j=a[1]++
m=a[i++]
Write i, j, m
Integer i=0,j
While(i<2)
{

j=0;
while(j<=3*i)
{
print j
print blank space
j=j+3
}
Print end-of-line
I=i+1
}
integer i=1 //STATEMENT 1
while(i<=3)
{
int j //STATEMENT 2
while (j<=i) //STATEMENT 3
{
print j
print blank space
j=j+1 //STATEMENT 4
}
Print end-of-line
i=i+1
}
//Sum of the first 10 multiples of 10.
Integer i=0 //Statement 1 Integer
sum=0 //Statement 2
While(i<=1000){ //Statement 3
sum=sum+i //Statement 4
---MISSING STATEMENT---
}
Print sum
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