Adam’s Charity
Adam decides to be generous and do some charity. starting today, from day 1 until day n, he gives i^2 coins to charity on day ‘i’ (1<=i<=n).
return the total coins he would give to charity.
Input specification:
Input 1: number of days of Charity.
Output Specification:
Return the total number of coins till charity days.
Example 1:
Input 1: 2
Output: 5
Explanation:
There are 2 days.
Example 2:
Input 1: 3
Output: 14
Explanation:
There are 3 days.
Solution in Python 3:
# https://codewindow.in
n=int(input())
sum=0
for i in range(1,n+1):
sum=sum+(i**2)
print(sum)
#join Telegram @codewindowSolution in C++ :
//https://codewindow.in
//join our telegram channel @codewindow
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
int n;
cin >> n;
int sum = 0;
for(int i=1;i<=n;i++)
sum += pow(i,2);
cout << sum;
return 0;
}Solution in C :
//https://codewindow.in
//join our telegram channel @codewindow
#include <stdio.h>
#include <math.h>
int main()
{
int n;
scanf("%d",&n);
int sum = 0;
for(int i=1;i<=n;i++)
sum += pow(i,2);
printf("%d",sum);
return 0;
}
Solution in JAVA :
//https://codewindow.in
//join our telegram channel @codewindow
import java.util.*;
class CodeWindow {
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int sum = 0;
for(int i=1;i<=n;i++)
sum += Math.pow(i,2);
System.out.println(sum);
}
}Output:
3
14