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Hackwithinfy 2021 Solution | Adventure Code

Question: Adventure Code

Solution: In Python 3

n = int(input())
    m = int(input())

    typelst = []
    for i in range(n): typelst.append(int(input()))
    timelst = []
    for i in range(n): timelst.append(int(input()))

    lst1 = []
    lst2 = []
    lst3 = []

    for i in range(n):
        if typelst[i] == 1:
            lst1.append(timelst[i])
        elif typelst[i] == 2:
            lst2.append(timelst[i])
        elif typelst[i] == 3:
            lst3.append(timelst[i])

    lst1.sort()
    lst2.sort()
    lst3.sort()
    
    for i in range(1,len(lst1)):
        lst1[i] += lst1[i-1]
    
    for i in range(1,len(lst2)):
        lst2[i] += lst2[i-1]

    for i in range(1,len(lst3)):
        lst3[i] += lst3[i-1]

    ans = math.inf
    
    try:
        ans = lst1[m-1] + lst2[m-1]
    except:
        pass

   

    for i in range(m):

        if i < len(lst3):
            if i==m-1:
                try:
                    val = lst3[i]
                    if val < ans: ans = val
                except: 
                    pass
            try:
                indx = m-i-2
                val = lst3[i] + lst2[indx] + lst1[indx]
                if val < ans: ans = val  
            except:
                pass
    
    if ans==math.inf:
        print(-1)
    else:
        print(ans)