Question 2

#### Let x be the least number which when divided by 12,15,18,20,27 and 30, the remainder in each case is 1 and x is a multiple of 47. The sum of the digits of x is:

#### a. 13

b. 11

c. 9

d. 10

Answer

#### d. 10

Explanation

#### LCM of 12,15,18,20,27, 30 is 540

Number should be divisible by 47 if we multiply k by 540 and add 1 then the number is divisible

by 47

540k + 1/ 47

Put value of k as 1,2

For k=2

540 * 2 +1 = 1081 which is divisible by 47

1081/47=23

So the digit is 1081

Addition of digits = 10